2(x^2-4x+4)+7=2x^2-8x+15

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Solution for 2(x^2-4x+4)+7=2x^2-8x+15 equation: 



2(x^2-4x+4)+7=2x^2-8x+15

We move all terms to the left:

2(x^2-4x+4)+7-(2x^2-8x+15)=0

We multiply parentheses

2x^2-8x-(2x^2-8x+15)+8+7=0

We get rid of parentheses

2x^2-2x^2-8x+8x-15+8+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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